Question

An iceberg is floating partially immersed in sea water. The density of sea water is $1.03gc{m}^{-3}$ and that of ice is 0.92 $gc{m}^{-3}$. The approximate percentage of total volume of iceberg above the level of sea water is

• A. 8
• B. 11
• C. 34
• D. 89

Answer 1

The correct option is B 11

lets say $V$ is the total volume of the iceberg, and $x$ be the volume of submerged part of iceberg. then according to Archimedes principle, we have
weight of the iceberg= weight of the water displaced (weight of $x$ volume of water)
$\Rightarrow V\times 0.92\times g=x\times 1.03\times g\Rightarrow \frac{x}{V}=\frac{92}{103}$
percentage of volume of iceberg submerged in sea water $=\frac{92}{103}\times 100=89.32$%
so percentage of total volume of iceberg above the level of sea water $=100-89.32=10.68$%$\approx 11$%