An ideal gas expands in volume from 1-10-3m3 to 1-10-2m3 at 300K against a constant pressure of 1-105Nm-2- The work done is-

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An ideal gas ...

Question

An ideal gas expands in volume from $1 \times 10^{- 3} m^{3}$ to $1 \times 10^{- 2} m^{3}$ at $300 K$ against a constant pressure of $1 \times 10^{5} {N m}^{- 2}$ . The work done is:

- 900 J

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- 1000 J

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270 k J

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+ 900 k J

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Solution

The correct option is A $- 900 J$
Work done at constant temperature is

$W$ = $- P Δ V$

$W$ = $-$ ( $P$ ) x ( $V_{2} - V_{1}$ )

$W$ = $-$ ( $1$ x $10^{5}$ ) x ( $10^{- 2}$ - $10^{- 3}$ )

$W$ = $-$ $900 J$

Hence, the correct option is $D$

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An ideal gas expands in volume from 1×10−3m3 to 1×10−2m3 at 300K against a constant pressure of 1×105Nm−2. The work done is:

The correct option is A −900JWork done at constant temperature is W = −PΔVW = − (P) x (V2−V1)W = − (1 x 105) x (10−2 - 10−3)W = − 900JHence, the correct option is D

An ideal gas expands in volume from $1 \times 10^{- 3} m^{3}$ to $1 \times 10^{- 2} m^{3}$ at $300 K$ against a constant pressure of $1 \times 10^{5} {N m}^{- 2}$ . The work done is:

The correct option is A $- 900 J$
Work done at constant temperature is

$W$ = $- P Δ V$

$W$ = $-$ ( $P$ ) x ( $V_{2} - V_{1}$ )

$W$ = $-$ ( $1$ x $10^{5}$ ) x ( $10^{- 2}$ - $10^{- 3}$ )

$W$ = $-$ $900 J$

Hence, the correct option is $D$