An ideal gas expands in volume from $10^{- 3}$ to $10^{- 2} m^{3}$ at 300 K against a constant pressure of $10^{5}$ Pa. Work done is

- 900 J

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- 900 kJ

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- 270 kJ

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900 kJ

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Solution

The correct option is A - 900 J
$w = - P Δ V$
$= - 10^{5} (10^{- 2} - 10^{- 3})$
$= - 900 J$

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