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Question
An ideal gas expands isothermally from 10−3 m3 to 10−2 m3 at 300 K against a constant pressure of 105N m−2. The work done on the gas is
An ideal gas expands isothermally from 10−3 m3 to 10−2 m3 at 300 K against a constant pressure of 105N m−2. The work done on the gas is
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Solution
Step 1:
P = 1×105Nm−2
Vi=1×10−3m3
Vf=1×10−2m2
ΔV=Vf−Vi = 10−2−10−3=9×10−3m3
Step 2:
W=−PdV=−P(V2−V1)
W=−105Nm−2×(10−2−10−3)m3=−105N m−2×(9×10−3) m3
W=−9×102Nm=−900 J (1 J=1 N m)
Hence, the work done is 900 J.
Step 1:
P = 1×105Nm−2
Vi=1×10−3m3
Vf=1×10−2m2
ΔV=Vf−Vi = 10−2−10−3=9×10−3m3
Step 2:
W=−PdV=−P(V2−V1)
W=−105Nm−2×(10−2−10−3)m3=−105N m−2×(9×10−3) m3
W=−9×102Nm=−900 J (1 J=1 N m)
Hence, the work done is 900 J.
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