Question

An ideal gas heat engine operates in Carnot cycle between ${227}^{o}C$ and ${127}^{o}C$. It absorbs $6\times {10}^{4}cal$ of heat at high temperature. Mass of heat converted to work is:

• A. $1.2\times {10}^{4}cal$
• B. $4.8\times {10}^{4}cal$
• C. $6\times {10}^{4}cal$
• D. $2.4\times {10}^{4}cal$

Answer 1

The correct option is A $1.2\times {10}^{4}cal$

$\eta =\frac{T_2-T_1}{T_2}=\frac{500-400}{500}=\frac{1}{5}$
$\therefore w=\eta \times Q=\frac{1}{5}\times 6\times {10}^4=1.2\times {10}^4$.