An ideal gas is taken through a cycle ABCA as shown in P – V diagram. The work done during the cycle is

$\frac{1}{2} P V$

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$2 P V$

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$4 P V$

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$P V$

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Solution

The correct option is D
$P V$

Work done $= \frac{1}{2} (B C) \times (A B)$

$= \frac{1}{2} (3 V - V) \times (2 P - P)$

$= P V$

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Similar questions

An ideal gas is taken around the cycle ABCA as shown in P-V diagram.

The net work done by the gas during the cycle is equal to:

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