An ideal gas is taken through the cycle $A \to B \to C \to A$ , as shown in the figure. If the net heat supplied to the gas in the cycle is 5 J, the work done by the gas in the process $C \to A$ is

-5 J

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-10 J

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-15 J

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-20 J

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Solution

The correct option is A -5 J
For a cyclic process. Total work done $W_{A B} + W_{B C} + W_{C A}$
$\Rightarrow \frac{1}{2} \times 1.0 \times 10 = 10 \times (2 - 1) + 0 + W_{C A} [W_{S C} = 0$ since there is no change in volume along BC]
$\Rightarrow 5 J = 10 J + W_{C A} \Rightarrow W_{C A} = - 5 J$

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An ideal gas is taken through the cycle A→B→C→A, as shown in the figure. If the net heat supplied to the gas in the cycle is 5 J, the work done by the gas in the process C→A is

The correct option is A -5 J For a cyclic process. Total work done WAB+WBC+WCA ⇒12×1.0×10=10×(2−1)+0+WCA[WSC=0 since there is no change in volume along BC] ⇒5J=10J+WCA⇒WCA=−5J

An ideal gas is taken through the cycle $A \to B \to C \to A$ , as shown in the figure. If the net heat supplied to the gas in the cycle is 5 J, the work done by the gas in the process $C \to A$ is

The correct option is A -5 J
For a cyclic process. Total work done $W_{A B} + W_{B C} + W_{C A}$
$\Rightarrow \frac{1}{2} \times 1.0 \times 10 = 10 \times (2 - 1) + 0 + W_{C A} [W_{S C} = 0$ since there is no change in volume along BC]
$\Rightarrow 5 J = 10 J + W_{C A} \Rightarrow W_{C A} = - 5 J$