An ideal gas is taken through the cycle ABCA a shown in the P-V diagram. The total work done by the gas during the cycle is

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2pV

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3pV

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6pV

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Solution

The correct option is C 3pV
Work done by the gas = area under P – V graph
$W = \frac{1}{2} \times A B \times A C \Rightarrow W = \frac{1}{2} \times 3 P \times 2 V$
W=3PV

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