Question

An ideal gas is taken via path $ABCA$ as shown in figure. The network done in the whole cycle is

• A. $3P_1{V}_1$
• B. $-3P_1{V}_1$
• C. $6P_1{V}_1$
• D. Zero

Answer 1

Answer: (B)

$-3P_1{V}_1$

W=area under the curve

$W=-\frac{3P_{1}2V_1}{2}=-3P_1{V}_1$