Question

An ideal gas occupies $2$ $cubicmeters$ at a pressure of $2$ $atm$. Taking $1$ atm. $={10}^5$ $Pa$, find the energy density of the gas.

Answer 1

Ideal gas volume$=2cc$

Pressure $2atm=2\times {10}^{5}Ps=2\times {10}^{5}N/m^2$

Energy density$=\rho =\frac{P}{V}=\frac{2\times {10}^{5}m/s}{2\times ({10}^{-2}{)}^3}={10}^{11}Kg/m^3$