Question

An ideal mono-atomic gas undergoes a cyclic process ABCA as shown in the figure. The ratio of heat absorbed during AB to the work done on the gas during BC is: $(\gamma =\frac{5}{3})$

• A. $\frac{5}{2ln2}$
• B. $\frac{5}{3}$
• C. $\frac{5}{4ln2}$
• D. $\frac{5}{6}$

Answer 1

Answer: (C)

$\frac{5}{4ln2}$

$Q_{AB}=n{C}_P\Delta T=\frac{nR\gamma \Delta T}{\gamma -1}$ Here AB process is constant pressure .
$W_{BC}=nRTln\frac{V_2}{V_1}$ Here BC process is constant temperature.