Question

An ideal monoatomic gas is taken round the cycle ABCDA as shown in the figure. The work done during the cycle is:

• A. $-PV$
• B. $-2PV$
• C. $-\frac{1}{2}PV$
• D. zero

Answer 1

The correct option is A $-PV$

Net work done is the area under the P-V curve.

Area = PV

Since the process is cyclic, net work done $=-PV$

Hence, option A is correct