$A n i d e a l n - c h a n n e l M O S F E T h a s t h e f o l l o w i n g p a r a m e t e r s, t h r e s h o l d v o l t a g e V_{T} = 0.65 V a n d o x i d e t h i c k n e s s i s 0.4 n m . I t i s f o u n d t h a t t h e M O S F E T o p e r a t i n g i n s a t u r a t i o n r e g i o n w i t h V_{D S} = 6 V . T h e n t h e p o w e r d i s s i p a t i o n i n t h e M O S F E T w i t h V_{G S} = 4 V i s μ_{n} C_{a x} \frac{W}{L} = 1.5 \times 10^{- 3} A / V^{2},$

50.50 m W

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37.65 m W

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25.25 m W

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75.50 m W

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Solution

The correct option is A $50.50 m W$
$G i v e n, μ_{n} C_{o x} \frac{W}{L} = 1.5 \times 10^{- 3} A / V^{2} V_{T} = 0.65 V V_{G s} = 4 V V_{D S} = 6 V p o w e r d i i p a t i o n i n t h e M O S F E T i s, P = V_{D S} \times I_{D S} W h e r e, I_{D S} i s d r a i n t o s o u r c e s a t u r a t i o n c u r r e n t . S i n c e t h e M O S F E T i s o p e r a t i n g i n s a t u r a t i o n r e g i o n, I_{D S} = \frac{1}{2} μ_{n} C_{o x} \frac{W}{L} (V_{G S} - V_{T})^{2} I_{D S} = 8.42 \times 10^{- 3} A p o w e r d i s s i p a t i o n, P = 6 \times 8.42 \times 10^{- 3} ∴ P = 50.50 m W$

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