An incompressible liquid flows through a horizontal tube as shown in figure, then the velocity $V$ of the fluid as given in the figure is

3 m / s

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1.5 m / s

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1 m / s

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2.25 m / s

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Solution

The correct option is C $1 m / s$
If the liquid is incompressible, then mass of liquid entering through left end should be equal to mass of liquid coming out from the right end $M = m_{1} + m_{2}$

$\frac{M}{t} = \frac{m_{1}}{t} + \frac{m_{2}}{t}$

$⟹ ρ (A V_{1}) = ρ (A V_{2} + 1.5 A . V)$

$A V_{1} = A V_{2} + 1.5 A . V$

$3 \times A = A \times 1.5 + 1.5 A \times V$

$⟹$ $V = 1 m / s$

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