An incompressible liquid flows through a horizontal tube as shown in the figure. Then the velocity of the fluid is:
Step 1: Given:
The velocity of the entering liquid,
The velocity of the liquid that is leaving through one of the pipes,
The cross-sectional area of the pipes mentioned above =
The cross-sectional area of the pipe through which the liquid is leaving with an unknown velocity =
Step 2: Finding the velocity of the liquid leaving through the pipe of cross-sectional area :
We know that the volume of the liquid entering the pipe = the volume of the liquid leaving the pipe.
Hence, the answer is (C)