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Question

An individual produces 4 different types of gametes. Find out the type of gametes and their frequency if the distance between the two genes is 18%.

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Solution

It is given that an individual produces 4 different types of gametes. Suppose the genes are A and B. Each gene has 2 forms, namely dominant (A and B) and recessive (a and b). Hence, the 4 types of gametes produced will be AB, Ab, aB and ab. The distance between two genes A and B is 18 cM or map unit. Now, a 1% percent recombination frequency is equivalent to 1 centimorgan or 1 map unit. Hence, the recombination frequency is 18%.

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