An inductance of 2H carries a current of 2A. To prevent sparking when the circuit is broken a capacitor of 4μF is connected across the inductance. The voltage rating of the capacitor is of the order of :
A
103V
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B
10V
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C
105V
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D
106V
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Solution
The correct option is A103V 12Li2=12CV2 ∴V=√LCi=√24×10−6(2)=√2×103V