An inductive circuit contains a resistance of 10 ohm and an inductance of 2.0 henry. If an ac voltage of 120 volt and frequency of 60 Hz is applied to this circuit, the current in the circuit would be nearly

0.32 amp

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0.16 amp

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0.48 amp

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0.80 amp

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Solution

The correct option is B 0.16 amp
$Z = \sqrt{R^{2} + X_{L}^{2}} = \sqrt{10^{2} + (2 π \times 60 \times 2)^{2}} = 753.7 ∴ i = \frac{120}{753.7} = 0.159 A$

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An inductive circuit contains a resistance of 10 ohm and an inductance of 2.0 henry. If an ac voltage of 120 volt and frequency of 60 Hz is applied to this circuit, the current in the circuit would be nearly

The correct option is B 0.16 ampZ=√R2+X2L=√102+(2π×60×2)2=753.7∴i=120753.7=0.159 A

The correct option is B 0.16 amp
$Z = \sqrt{R^{2} + X_{L}^{2}} = \sqrt{10^{2} + (2 π \times 60 \times 2)^{2}} = 753.7 ∴ i = \frac{120}{753.7} = 0.159 A$