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Question

An inductor of 12 mH and a resistor of 4 KΩ are connected in series across a battery of 240 V through a switch. After closing the switch the current in the circuit starts growing. When the current is 15 mA, the potential difference across the inductor will be:

A
60 V
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B
120 V
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C
180 V
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D
240v
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Solution

The correct option is C 180 V
i=ER(1eRtL)
15×103=2404×103(1e4t×10312×103)
e106t3=34
V=EeRtL
=E×34
=240×34
=180V

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