Question

Two inductors $L_1$(inductance 1 mH, internal resistance 3 $\Omega$) and $L_2$(inductance 2 mH, internal resistance 4 $\Omega$), and a resistor R (resistance 12 $\Omega$) are all connected in parallel across a 5 V battery. The circuit is switched on at time t=0. The ratio of the maximum to the minimum current ($I_{max}/I_{min}$) drawn from the battery is :

Answer 1

$i_{min}=\frac{5}{12}$ at $t=0^{+}$

$i_{max}=\frac{5\times 8}{12}$ at $t=\infty$

$\frac{i_{max}}{i_{min}}=8$