An inorganic compound $(A)$ of $S, C l$ and oxygen has vapour density $67.5$ . It reacts with water to form two acids $(B)$ and $(C)$ . $(A)$ also reacts with ${K O H}_{(a q)}$ to form two salts $(D)$ and $(E)$ . $(D)$ and $(E)$ gives white precipitate with $A g {N O}_{3}$ and $B a {C l}_{2}$ solutions respectively. What are $(A)$ to $(E)$ ?

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Solution

Vapour density of $S, C l$ and oxygen compound $= 67.5$
$∴$ Molecular weight of compound $= 135$
the molecular weight suggest it may be ${S O}_{2} {C l}_{2}$
The given reaction are
$(i) {S O}_{2} {C l}_{2} (A) + 2 H_{2} O ⟶ 2 H C l (B) + H_{2} {S O}_{4} (C)$
$(i i) {S O}_{2} {C l}_{2}$ + $4 K O H$ $⟶$ $K_{2} {S O}_{4} (D)$ + $2 K C l (E) + 2 H_{2} O$
$(i i i) K_{2} {S O}_{4} (D) + B a {C l}_{2} ⟶ B a {S O}_{4} I n s o l u b l e + 2 K C l$
$K C l (E) + A g {N O}_{3} ⟶ A g C l I n s o l u b l e + {K N O}_{3}$

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