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Question

An inorganic halide (A) gives the following reations:
(i) the cation of (A) on reaction with H2S in HCl medium, gives a black ppt. of (B). (A) neither gives ppt. with HCl nor blue colour with K4Fe(CN)6.
(ii) (B) on heating with dil. HCl gives back compound (A) and a gas (C) which gives a black ppt. With lead acetate solution.
(iii) the anion of (A) gives chromyl chloride test.
(iv) (B) dissolves in hot dil. HNO3 to give a solution, (D). (D) gives ring test.
(v) when NH4OH solution is added to (D), a white precipitate (E) is formed. (E) dissolves in minimum amount of dil. HCl to give a solution of (A). Aqueous solution of (A) on addition of water gives a whitish turbidity (F).
(vi) aqueous solution of (A) on warming with alkaline sodium stannite gives a black precipitate of a metal (G) and sodium stannate. The metal (G) dissolves in hydrochloride acid to give solution of A.


Identify (F) and (G) and give balanced chemical equations of reactions.

A
(F)BiOCl(G)Bi
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B
(F)SiOCl(G)Si
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C
(F)PbOCl(G)Pb
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D
None of these
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Solution

The correct option is A (F)BiOCl(G)Bi
(i) BiCl3[A]+H2SBi2S3[B]+HCl

(ii)Bi2S3+HClBiCl3+H2S[C]

H2S+(CH3COO)2PbPbS(blackppt)+CH3COOH

(iii) BiCl3+K2Cr2O7+H2SO4KHSO4+CrO2Cl2+NaHSO4+H2O

(iv) Bi2S3+HNO3Bi(NO3)3[D]+NO+S+H2O
Ring test is due to nitrate anion.

(v) Bi(NO3)3+NH4OHBi(OH)3[E]+NH4NO3
Bi(OH)3+HClBiCl3+H2O

BiCl3+H2OBiOCl[F]+HCl

(vi) BiCl3+Na2SnO2+NaOHNa2SnO3+Bi[G]+NaCl+H2O

Bi+HClBiCl3+H2

Thus, (F) is BiOCl and (G) is Bi

Hence, the correct option is A

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