An insect moves along a circular path of radius 10 cm with a constant speed. If it takes 1 minute to move from a point on the path to the diametrically opposite point, then the distance covered, speed, displacement and average velocity respectively are

3.14 cm, 3.14 cm/min, 10 cm, 10 cm/min

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31.4 cm, 31.4 cm/min, 20 cm, 0.33 cm/s

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0.314 cm, 0.314 cm/min, 1cm, 1 cm/min

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314 cm, 314 cm/min, 0.1 cm, 0.1 cm/min

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Solution

The correct option is B
31.4 cm, 31.4 cm/min, 20 cm, 0.33 cm/s

The distance covered = $π r$ = 3.14 $\times$ 10
=31.4 cm
Speed $= \frac{d i s t a n c e}{t i m e} = \frac{31.4}{1 m i n}$
=31.4 cm/min
Displacement = 2r = 2 $\times$ 10 = 20 cm.
Average velocity $= \frac{d i s p l a c e m e n t}{t i m e}$
$\frac{20}{60} = \frac{20 c m}{60 s e c} = 0.33 c m / s$

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An insect moves along a circular path of radius 10 cm with a constant speed. If it takes 1 minute to move from a point on the path to the diametrically opposite point, then the distance covered, speed, displacement and average velocity respectively are

The correct option is B 31.4 cm, 31.4 cm/min, 20 cm, 0.33 cm/s The distance covered = πr = 3.14 × 10 =31.4 cm Speed =distancetime=31.41 min =31.4 cm/min Displacement = 2r = 2 × 10 = 20 cm. Average velocity =displacementtime 2060=20 cm60 sec=0.33 cm/s