An insect moves along a circular path of radius 10 cm with a constant speed. If it takes 1 minute to move from a point on the path to the diametrically opposite point, then, the following quantities:
1. Distance covered
2. Speed
3. Displacement
4. Average velocity
will be respectively:

3.14 cm
3.14 cm/min
10 cm
10 cm/min

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31.4 cm
31.4 cm/min
20 cm
0.33 cm/s

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0.314 cm
0.314 cm/min
1cm
1 cm/min

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314 cm
314 cm/min
0.1 cm
0.1 cm/min

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Solution

The correct option is B
31.4 cm
31.4 cm/min
20 cm
0.33 cm/s

1. The distance covered = $π r = 3.14 \times 10 = 31.4 c m .$

2. Speed $= \frac{d i s t a n c e c o v e r e d}{t i m e} = \frac{31.4 c m}{1 m i n} = 31.4 c m / m i n .$

3. Displacement = length of diameter
$= 2 r = 2 \times 10 = 20 c m .$

And, 4. Average velocity $= \frac{d i s p l a c e m e n t}{t i m e} = \frac{20 c m}{60 s e c} = 0.33 c m / s$

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An insect moves along a circular path of radius 10 cm with a constant speed. If it takes 1 minute to move from a point on the path to the diametrically opposite point, then, the following quantities: 1. Distance covered 2. Speed 3. Displacement 4. Average velocity will be respectively:

The correct option is B 31.4 cm 31.4 cm/min 20 cm 0.33 cm/s 1. The distance covered = πr=3.14×10=31.4 cm. 2. Speed =distance coveredtime=31.4 cm1 min=31.4 cm/min. 3. Displacement = length of diameter =2r=2×10=20 cm. And, 4. Average velocity =displacementtime=20 cm60 sec=0.33 cm/s

An insect moves along a circular path of radius 10 cm with a constant speed. If it takes 1 minute to move from a point on the path to the diametrically opposite point, then, the following quantities:
1. Distance covered
2. Speed
3. Displacement
4. Average velocity
will be respectively: