An inverted tube barometer is kept in a lift moving vertical upward with an acceleration -a- The density of mercury is - and acceleration due to gravity isg- If the atmospheric pressure be P 0 thenA- Height of the mercury column in the lift will be P 0- - aB- Height of the mercury column in the lift will be Po-g-aC- Height of the mercury column in the lift will be Po-g-aD- Height of the mercury column in the lift will be P-

The correct option is C P_o = ρ(g+a)h ⇒ h = P_o/ρ (g+a) ...

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Standard XII

Physics

Atmospheric Pressure

An inverted t...

Question

An inverted tube barometer is kept in a lift moving vertical upward with an acceleration 'a'. The density of mercury is $ρ$ and acceleration due to gravity is g. If the atmospheric pressure be $P_{o}$ then

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Solution

The correct option is A

$P_{o}$ = $ρ$ (g+a)h

$\Rightarrow$ h = $\frac{P_{o}}{ρ (g + a)}$

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An inverted tube barometer is kept in a lift moving vertical upward with an acceleration 'a'. The density of mercury is ρ and acceleration due to gravity is g. If the atmospheric pressure be Po then

The correct option is A Po = ρ(g+a)h ⇒ h = Poρ(g+a)

An inverted tube barometer is kept in a lift moving vertical upward with an acceleration 'a'. The density of mercury is $ρ$ and acceleration due to gravity is g. If the atmospheric pressure be $P_{o}$ then

The correct option is A

$P_{o}$ = $ρ$ (g+a)h

$\Rightarrow$ h = $\frac{P_{o}}{ρ (g + a)}$