An ion $M^{3 +}$ has electronic configuration $[A r] 3 d^{10} 4 s^{2}$ . Element M belongs to :

s- block

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p - block

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d - block

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f- bblock

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Solution

The correct option is A p - block
$M^{3 +}$ has configuration $[A r] 3 d^{10} 4 s^{2}$

$M^{3 +}$ has lose $3 e^{-}$

$M$ has configuration $[A r] 3 d^{10} 4 s^{2} 4 p^{3}$

Hence, the element M belongs to p - block.

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M^{3 +}

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