Question

An iron ball of mass $100$gm is heated to ${100}^o$C and is put on a block of ice at $0^o$C. If $12.5$gm of ice melts, what is the specific heat of iron $(L=80cal{g}^{-1})$?

Answer 1

Heat released by the iron ball= heat absorbed by the ice block.

$mS\Delta t=ML$

where $m$= mass of the iron

$S$= specific heat

$=100\times S\times (100-0)=12.5\times 80$

$M$=mass of ice

$L$= latent heat of fusion of ice.

$S$=0.1

$\therefore$ specific heat of iron is 0.1 cal/g $°C$.