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Law of Conservation of Mechanical Energy

An iron ball ...

Question

An iron ball of mass 100 gm is heated to $100^{o} C$ and is put on a block of ice at $0^{o} C$ . If 12.5 gm of ice melts, what is the specific heat of iron $(L = 80 c a l g^{- 1})$ ?

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Solution

$H e a t l o s t b y a i r o n b a l l = l a t e n t h e a t t a k e n b y i c e$
$100 \times s \times 100 = 12.5 \times 80$
$\Rightarrow s = \frac{12.5 \times 80}{100 \times 100} = 0.1 c a l g^{- 1}^{o} C^{- 1}$

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