An iron block having dimensions 2 m - 2 m - 3 m has mass of 24 kg- Calculate the density of the iron- A- 2 kg m -3B- 1 kg m -3C- 3 kg m -3D- 4 kg m -3

The correct option is A 2 kg m^ 3 nbsp;Given, nbsp; Mass of the block = 24 kg Volume of the block = nbsp;2 m×2 m×3 m = 12 m^3 Density = Mass/Volume De ...

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Standard VII

Physics

Density

An iron block...

Question

An iron block having dimensions $2 m \times 2 m \times 3 m$ has mass of $24 k g$ . Calculate the density of the iron.

2 k g m^{- 3}

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1 k g m^{- 3}

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3 k g m^{- 3}

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4 k g m^{- 3}

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Solution

The correct option is A $2 k g m^{- 3}$
Given,
Mass of the block = $24 k g$
Volume of the block = $2 m \times 2 m \times 3 m$ = $12 m^{3}$
Density = $\frac{M a s s}{V o l u m e}$
Density of the iron = $\frac{24 k g}{12 m^{3}}$ = $2 k g m^{- 3}$

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An iron block having dimensions 2 m×2 m×3 m has mass of 24 kg. Calculate the density of the iron.

The correct option is A 2 kg m−3 Given, Mass of the block = 24 kg Volume of the block = 2 m×2 m×3 m = 12 m3 Density = MassVolume Density of the iron = 24 kg12 m3 = 2 kg m−3

An iron block having dimensions $2 m \times 2 m \times 3 m$ has mass of $24 k g$ . Calculate the density of the iron.

The correct option is A $2 k g m^{- 3}$
Given,
Mass of the block = $24 k g$
Volume of the block = $2 m \times 2 m \times 3 m$ = $12 m^{3}$
Density = $\frac{M a s s}{V o l u m e}$
Density of the iron = $\frac{24 k g}{12 m^{3}}$ = $2 k g m^{- 3}$