Question

An iron pillar has some part in the form of a right circular cylinder and remaining in the form of a right circular cone. The radius of base of each of cone and cylinder is $8/cm$. The cylindrical part is $240cm$ high and the conical part is $36cm$ high. Find
The volume of iron used

• A. $50688{cm}^3$
• B. $42652{cm}^3$
• C. $50878{cm}^3$
• D. None of these

Answer 1

The correct option is A $50688{cm}^3$

The volume of cylindrical part $=\pi r^{2}h$

$=\frac{22}{7}\times 8^2\times 240=48274.285$

The volume of conical part $=\frac{1}{3}\times b\times h$

$=\frac{1}{3}\times \frac{22}{7}\times 8^2\times 36=2413.7142$

Total volume $=48274.285+2413.7142$

$=50688c{m}^3$.