An isosceles trapezium has an area of 36 cm2- the parallel sides are 12 cm and 6 cm respectively- Find the height of the trapezium-

Let the height be 'h' cm. The area of a trapezium is given by: A=1/2×(Sum of parallel sides)×(height) ⇒36=1/2×(12+6)× h ⇒36=1/2× 18× h ⇒36=9× h ⇒ h=4 cm ...

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Byju's Answer

Standard VIII

Mathematics

Area of Isosceles Trapezium

An isosceles ...

Question

An isosceles trapezium has an area of 36 cm², the parallel sides are 12 cm and 6 cm respectively. Find the height of the trapezium.

4 cm

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Solution

The correct option is A
4 cm

Let the height be 'h' cm.

$The area of a trapezium is given by:$
$A = \frac{1}{2} \times (Sum of parallel sides) \times (height)$
$\Rightarrow 36 = \frac{1}{2} \times (12 + 6) \times h$

$\Rightarrow 36 = \frac{1}{2} \times 18 \times h$

$\Rightarrow 36 = 9 \times h$
$\Rightarrow h = 4 c m$

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An isosceles trapezium has an area of 36 cm2, the parallel sides are 12 cm and 6 cm respectively. Find the height of the trapezium.

The correct option is A 4 cm Let the height be 'h' cm. The area of a trapezium is given by: A=12×(Sum of parallel sides)×(height) ⇒36=12×(12+6)×h ⇒36=12×18×h ⇒36= 9×h ⇒h=4cm

An isosceles trapezium has an area of 36 cm², the parallel sides are 12 cm and 6 cm respectively. Find the height of the trapezium.