Question

An $L-C-R$ series circuit with $L=0.120H,R=240\Omega$, and $C=7.30\mu F$ carries an rms current of $0.450A$ with a frequency of $400Hz$. What is the average rate at which electrical energy is dissipated (converted to other forms) in the inductor?

Answer 1

$R=240\Omega ,C=7.3\mu F,L=0.12H,\omega =2\pi \times 400=2512$

RMS current is $i_r=0.45A$

The rate of thermal energy dissipated in Inductor is zero.

As instantaneous power $p_L=i_{m}sin(\omega t-\pi /2)\times v_{m}sin\omega t=-v_m{i}_{m}sin2\omega t/2$

Now average power in Inductor is $P_L=0$ as average of $sin2\omega t$ is $0$.