Question

An $L-C-R$ series circuit with $L=0.120H,R=240\Omega$, and $C=7.30\mu F$ carries an rms current of $0.450A$ with a frequency of $400Hz$. The average rate at which electrical energy is converted to thermal energy in the resistor is given as $\frac{x}{10}W$. Find $x$

Answer 1

$R=240\Omega ,C=7.3\mu F,L=0.12H,\omega =2\pi \times 400=2512$

RMS current is $i_r=0.45A$

The rate of thermal energy dissipated in resistor is given as $P=i_r^{2}R={0.45}^2\times 240=48.6W$

$\Rightarrow x/10=48.6\Rightarrow x=486$