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Question

An LCR circuit contains resistance of 110 Ω and a supply of 220 V at 300 rad/s angular frequency. If only capacitance is removed from the circuit, current lags behind the voltage by 45. If on the other hand, only inductor is removed the current leads by 45 with the applied voltage. The rms current flowing in the circuit will be:

A
2.5 A
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B
2 A
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C
1 A
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D
1.5 A
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Solution

The correct option is B 2 A
When L and C are connected with R in series the circuit will come in resonance So, current in the circuit will be:
Irms=VrmsR=220110=2 A

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