P1=12 ATM
T1=27'C or 273+27=300 K
P2=14.9 ATM
therefore, T2=(P2 x T1)/P1
(14.9 x 300)/12
=372.5 K or 372.5 -273=99.5'C(answer)
LPG cylinder can withstand a pressure of 14.9 atm. The pressure gauge of the cylinder reads 12 atm at 27°C. Due to a sudden fire in the building the temperature rises. Are what temperature will the cylinder explode?
L.P.G. cylinder can withstand a pressure of 14.9 atmosphere. The pressure gauge of the cylinder indicates 12 atmosphere at 27∘C Due to a sudden fire in the building the temperature rises. At what temperature will the cylinder explode.