Question

An $LPG$ cylinder contains gas at a pressure of $300kPa$ at ${27}^{\circ }$C. The cylinder can withstand the pressure of $1.2\times {10}^{6}Pa$. The room in which the cylinder is kept catches fire. The minimum temperature at which the bursting of cylinder will take place is ____ ${}^{\circ }$C. (Nearest Integer)
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Answer 1

At constant volume and number of moles of a gas, pressure is directly proportional to temperature change.
$\frac{P_1}{T_1}=\frac{P_2}{T_2}$
$T_2=\frac{1.2\times {10}^6}{300\times {10}^3}\times 300=1200K={927}^{o}C$