An n–p–n transistor circuit has α=0.985. If Collector current Ic=2 mA, then value of base current Ib is____.
Given α=0.985
α=IcIe=IcIc+Ib=0.985
Ic=0.985(Ic+Ib)
Ic=0.985 Ic+0.985 Ib
0.985 Ib=0.015 Ic=0.015×2 mA
Ib=0.015×20.985=0.03mA
Ib≈0.03 mA