An object 5 cm high is placed at a distance of 60 cm in front of a concave mirror of focal length 10 cm. Find the position and size of image.

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Solution

f = -10 cm

u = -60 cm

Mirror formula $\frac{1}{f}$ = $\frac{1}{v}$ + $\frac{1}{u}$

$\frac{1}{v}$ = $\frac{1}{f}$ – $\frac{1}{u}$

$\frac{1}{v}$ = $\frac{1}{- 10}$ + $\frac{1}{60}$

v = -12 cm

Image is formed at the same side of the mirror at a distance of 12 cm from the pole.

$\frac{h_{i}}{h_{o}}$ = $\frac{- v}{u}$

$\frac{h_{i}}{5}$ = $\frac{12}{- 60}$

$h_{i}$ = -1 cm

Image is inverted and its size is 1 cm.

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An object 5 cm high is placed at a distance of 60 cm in front of a concave mirror of focal length 10 cm. Find the position and size of image.

f = -10 cm u = -60 cm Mirror formula 1f = 1v + 1u 1v = 1f – 1u 1v = 1−10 + 160 v = -12 cm Image is formed at the same side of the mirror at a distance of 12 cm from the pole. hiho = −vu hi5 = 12−60 hi = -1 cm Image is inverted and its size is 1 cm.