An object A is moving with 10m/s and B is moving with 5m/s in the same direction as shown. Initially A is 100m behind B as shown. Find the time taken by A to meet B
A
18s
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B
16s
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C
20s
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D
17s
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Solution
The correct option is C20s Let us solve the problem in a frame relative to object B. So, we have velocity of object A w.r.t to object B as VAB=VA−VB=10−5=5m/s And, distance between the two objects is 100m
∴ time taken by A to meet B is given by t=100VAB=1005=20sec