An object at a depth of $10 c m$ in water seems to depth of (refractive index of water $= 4 / 3$ ):

2.5 c m

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5 c m

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6.5 c m

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7.5 c m

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Solution

The correct option is D $7.5 c m$
$\begin{matrix} h_{apparent} & = μ_{observer} (\frac{h_{1}}{μ_{1}}) μ_{observer} & = 1, μ_{1} = 4 / 3; h_{1} = 10 c m h_{apparent} & = 1 \times (\frac{10}{4 / 3}) = \frac{30}{4} = 7.5 c m \end{matrix}$

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An object at a depth of 10 cm in water seems to depth of (refractive index of water =4/3):

The correct option is D 7.5 cmhapparent =μobserver (h1μ1)μ observer =1,μ1=4/3;h1=10 cmh apparent =1×(104/3)=304=7.5 cm

An object at a depth of $10 c m$ in water seems to depth of (refractive index of water $= 4 / 3$ ):

The correct option is D $7.5 c m$
$\begin{matrix} h_{apparent} & = μ_{observer} (\frac{h_{1}}{μ_{1}}) μ_{observer} & = 1, μ_{1} = 4 / 3; h_{1} = 10 c m h_{apparent} & = 1 \times (\frac{10}{4 / 3}) = \frac{30}{4} = 7.5 c m \end{matrix}$