An object at rest starts moving at a uniform acceleration of 2 ms−2. The distance travelled by it in 2 s is
4 m
Given, acceleration a=2 ms−2, initial velocity u=0 ms−1 and time t=2 s.
Let distance travelled be s.
We use second equation of motion, s=ut+12at2.
So, s=0×2+122×22
On soving we get s=4 m
Therefore, distance travelled by it in 2 s is 4 m.