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Apparent Depth

An object at ...

Question

An object at the bottom of a beaker filled with a liquid up to height of 10 cm. If the refractive index of liquid w.r.t. air ( ^aµ_w ) is 4/3, find the apparent depth of the object.

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Solution

Real depth = 10 cm
^aµ_w = 4/3
µ = Real depth / Apparent depth
4/3 = 10 / Apparent depth
Apparent depth = 10 X 3 / 4
= 30 / 4
= 7. 5 cm (Ans.)

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