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Standard IX

Physics

Derivation of Velocity-Time Relation by Graphical Method

An object dro...

Question

An object drop from a with a constant acceleration of $10 m / s^{2}$ . Find its speed 2 sec after it was dropped.

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Solution

Given, $a = 10 m / s^{2}$
$u = 0 m / s$ (dropping)
$t = 2 s e c$
So, $v = u + a t$
$= 0 + 10 (2)$
$= 20 m / s$
Velocity after $2 s e c = 20 m / s$

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An object drop from a with a constant acceleration of 10m/s2 . Find its speed 2 sec after it was dropped.

Given, a=10m/s2u=0m/s (dropping)t=2secSo, v=u+at=0+10(2)=20m/sVelocity after 2sec=20m/s

An object drop from a with a constant acceleration of $10 m / s^{2}$ . Find its speed 2 sec after it was dropped.

Given, $a = 10 m / s^{2}$
$u = 0 m / s$ (dropping)
$t = 2 s e c$
So, $v = u + a t$
$= 0 + 10 (2)$
$= 20 m / s$
Velocity after $2 s e c = 20 m / s$