An object exerts a normal force F on a surface of area A, and pressure P acting on the surface is.

$P = \frac{F}{A}$

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$P = F \times A$

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$P = \frac{A}{F}$

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$P = \frac{F}{A^{2}}$

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Solution

The correct option is A
$P = \frac{F}{A}$

Explanation for correct option(s):-
Pressure is defined as the amount of force acting along the surface area.
correct option (A) :- $P = \frac{F}{A}$
SI unit:- $\frac{N}{m^{2} o r P a s c a l (P a)}$
Hence, option (A) is correct.

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An object exerts a normal force F on a surface of area A, and pressure P acting on the surface is.

The correct option is A P=FAExplanation for correct option(s):- Pressure is defined as the amount of force acting along the surface area.correct option (A) :- P=FASI unit:- Nm2orPascal(Pa)Hence, option (A) is correct.

The correct option is A
$P = \frac{F}{A}$

Explanation for correct option(s):-
Pressure is defined as the amount of force acting along the surface area.
correct option (A) :- $P = \frac{F}{A}$
SI unit:- $\frac{N}{m^{2} o r P a s c a l (P a)}$
Hence, option (A) is correct.