An object hangs from a spring balance. The balance indicates 40N in air and 20N when the object is submerged in water. What does the balance indicate when the object is submerged in a liquid with a density that is half that of water?
A
20N
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B
25N
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C
30N
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D
35N
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Solution
The correct option is B30N The approximate force applied by the mass of the object is 40N- since the mass of the air being displaced is negligible when compared to the other fluids used in this question. In case of submerging ,the volume of water displaced accounts for 20N (40−20=20N). If a fluid with half this density is used, only half as many Newtons will be relived from the balance ⇒20N2=10N So in second case reading of balance =40N−10N=30N