Question

An object is dropped from a cliff falls with a constant acceleration of $10m/s^2$. Find its speed 2s after it was dropped.

Answer 1

Step1: Given:

$$\begin{gathered} Initialspeed\left(v\right)=0m/s \\ Acceleration\left(a\right)=10m/s^2 \\ Time\left(t\right)=2s \end{gathered}$$

Step 2:Formula used:

$v=u+at[where,visinitialvelocity,uisfinalvelocity,aisaccelerationandtistime]$

Step 3: Final solution:

$$\begin{gathered} v=u+at \\ v=0+10\times 2 \\ v=20m/s \end{gathered}$$

Thus the initial velocity of an object is $20m/s$