An object is placed at $30 c m$ in front of the convex lens of focal length $10 c m$ . Find out the image distance from the lens?

-15 cm

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+20 cm

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+ 15 cm

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-20 cm

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Solution

The correct option is C
+ 15 cm

From Len's formula, $\frac{1}{v}$ - $\frac{1}{u}$ = $\frac{1}{f}$

$f = + 10 c m$ (convex lens)

$u = - 30 c m$

$\frac{1}{v}$ + $\frac{1}{30}$ = $\frac{1}{10}$

$\frac{1}{v}$ = $\frac{1}{10}$ - $\frac{1}{30}$ = + $\frac{2}{30}$

$v = + 15 c m$

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An object is placed at 30 cm in front of the convex lens of focal length 10 cm. The distance of the image from the lens is + ___ cm.

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An object is placed at 30 cm in front of the convex lens of focal length 10 cm. Find out the image distance from the lens?

The correct option is C + 15 cm From Len's formula, 1v - 1u = 1f f = + 10 cm (convex lens) u = − 30 cm 1v + 130 = 110 1v = 110 - 130 = + 230 v = + 15 cm

An object is placed at $30 c m$ in front of the convex lens of focal length $10 c m$ . Find out the image distance from the lens?

The correct option is C
+ 15 cm

From Len's formula, $\frac{1}{v}$ - $\frac{1}{u}$ = $\frac{1}{f}$

$f = + 10 c m$ (convex lens)

$u = - 30 c m$

$\frac{1}{v}$ + $\frac{1}{30}$ = $\frac{1}{10}$

$\frac{1}{v}$ = $\frac{1}{10}$ - $\frac{1}{30}$ = + $\frac{2}{30}$

$v = + 15 c m$