An object is place at 4 cm distance in front of a concave mirror of radius of curvature 24 cm. find the position of the image.

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Solution

u = -4 cm

f = - 12 cm

Mirror formula $\frac{1}{f}$ = $\frac{1}{v}$ + $\frac{1}{u}$

$\frac{1}{v}$ = $\frac{1}{f}$ – $\frac{1}{u}$

$\frac{1}{v}$ = $\frac{1}{- 12}$ + $\frac{1}{4}$

v = 6 cm.

Image is 6 cm from the pole behind the mirror.

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An object is place at 4 cm distance in front of a concave mirror of radius of curvature 24 cm. find the position of the image.

u = -4 cm f = - 12 cm Mirror formula 1f = 1v + 1u 1v = 1f – 1u 1v = 1−12 + 14 v = 6 cm. Image is 6 cm from the pole behind the mirror.

u = -4 cm

f = - 12 cm

Mirror formula $\frac{1}{f}$ = $\frac{1}{v}$ + $\frac{1}{u}$

$\frac{1}{v}$ = $\frac{1}{f}$ – $\frac{1}{u}$

$\frac{1}{v}$ = $\frac{1}{- 12}$ + $\frac{1}{4}$

v = 6 cm.

Image is 6 cm from the pole behind the mirror.