An object is placed at 60 cm from the pole of a concave mirror, whose focal length is 20 cm. Find the distance at which the image is formed.

v = – 20 cm

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v = – 30 cm

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v = + 30 cm

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v = + 20 cm

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Solution

The correct option is B
v = – 30 cm

$\frac{1}{v}$ + $\frac{1}{u}$ = $\frac{1}{f}$

u = -60 cm, f = - 20 cm (using the sign conventions)

$\frac{1}{v}$ - $\frac{1}{60}$ = $\frac{- 1}{20}$

$\frac{1}{v}$ = $\frac{- 1}{30}$

v = - 30 cm (with sign convention)

i.e, v = 30 cm on the side of object

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An object is placed at 60 cm from the pole of a concave mirror, whose focal length is 20 cm. Find the distance at which the image is formed.

The correct option is B v = – 30 cm 1v + 1u = 1f u = -60 cm, f = - 20 cm (using the sign conventions) 1v - 160 = −120 1v = −130 v = - 30 cm (with sign convention) i.e, v = 30 cm on the side of object

The correct option is B
v = – 30 cm

$\frac{1}{v}$ + $\frac{1}{u}$ = $\frac{1}{f}$

u = -60 cm, f = - 20 cm (using the sign conventions)

$\frac{1}{v}$ - $\frac{1}{60}$ = $\frac{- 1}{20}$

$\frac{1}{v}$ = $\frac{- 1}{30}$

v = - 30 cm (with sign convention)

i.e, v = 30 cm on the side of object