An object is placed in front of a glass slab $(μ = 1.5)$ of thickness $6 c m$ at a distance $28 c m$ from it. Other face of glass slab is silvered. Find the position of final image of object.

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Solution

Shift $= t (1 - \frac{n_{2}}{n_{1}})$

$= 6 (1 - \frac{1}{1.5}) = 6 (\frac{0.5}{1.5})$

Shift $= 2$

So, $ν = 28 - 2$
$= 26 c m$

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